Geometry Problem
Level: Mathematics Education, High School, Honors Geometry, College.
Click the figure below to see the complete problem 772.
Friday, June 22, 2012
Problem 772: Similar triangles with a Common Vertex, Equal Angles, Midpoints, Metric relations
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ReplyDeleteConnect lines as shown on the sketch
We have DE=1/2*BB’ and DF=1/2*CC’
So DE/DF=BB’/DC
∆ABC similar to ∆AB’C’ …( Case AA)
So AB’/AB=AC’/AC and AB’/AC’=AB/AC=5/6
∆AB’B similar to ∆AC’C …. ( case SAS)
So BB’/CC’=AB’/AC’=5/6
DE/DF=5/6
DF=24/5