Geometry Problem
Level: Mathematics Education, High School, Honors Geometry, College.
Click the figure below to see the problem 744 details.
Sunday, April 29, 2012
Problem 744: Parallelogram, Circle, Diameter, Chord, Congruence, Triangle
Subscribe to:
Post Comments (Atom)
http://img191.imageshack.us/img191/1969/problem744.png
ReplyDeleteDraw GN//AB ( see sketch)
Since GF=GH => ∠ (FBG)= ∠ (GBH)
We also have ∠ (BGA)= ∠ (NBG)= ∠ (GBH)= ∠ (GBA)….(Alternate angles)
So triangles BNG isosceles and NB=BA=NG=4
In right triangle BGM, GN is a median and BM= 2*BN= 8
So CM= BM-BC= 3