Geometry Problem
Level: Mathematics Education, High School, Honors Geometry, College.
Click the figure below to see the complete problem 684.
Wednesday, November 2, 2011
Problem 684: Outer Nagel Point, Triangle, Excircles, Tangency points, Concurrent lines, Semi-perimeter, Ceva theorem
Subscribe to:
Post Comments (Atom)
AB':B'C = (s - a):(s - c)
ReplyDeleteCA':A'B = s:(s - a)
BC':C'A = (s - c): s
Product = 1
So AA', BB', CC' are concurrent (by Ceva)
Is there a solution using only projective geometry?
ReplyDelete