Geometry Problem
Level: Mathematics Education, High School, Honors Geometry, College.
Click the figure below to see the complete problem 628.
Thursday, June 23, 2011
Problem 628: Cyclic Quadrilateral, Congruence, Parallel Lines
Labels:
congruence,
cyclic quadrilateral,
parallel
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Isosceles Triangles ABE and DCF are equiangular
ReplyDelete(vertical angles at B and C being equal).
So
<AEB = <DFC,
and on taking supplements
<AED = <AFD
and thus
A,E,F,D are concyclic
Now <AFE = <ADB = <ACB
Hence EF // BC