Sunday, June 12, 2011

Problem 622: Intersecting Circles, Concyclic Points, Centers, Radii

Geometry Problem
Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to see the complete problem 622.

Online Geometry Problem 622: Intersecting Circles, Concyclic Points, Centers, Radii.

Posted by Antonio Gutierrez at 10:02 PM
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2 comments:

  1. EditorJune 13, 2011 at 4:30 PM

    tr BEC isosceles => ang CEB= ang ECB=a
    tr CAF isosceles => ang CFA= ang ACF=a
    thus AEFB is cyclic.
    ACBD is a deltoid so ang D = ang C and therefore ang AEB+ ang ADB= ang AEB+ ang ACB=180 => AEBD is cyclic.
    finally AEFBD is cyclic.

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  2. Sumith PeirisNovember 29, 2015 at 9:12 AM

    Tr.s ACB and ADB are congruent hence < ADB = < ACB = < AFB since AC = AF so ADFB is cyclic. Similarly ADBE is cyclic

    So AEFBD is cyclic

    Sumith Peiris
    Moratuwa
    Sri Lanka

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