Friday, April 29, 2011

Geometry Problem 597: Quadrilateral, Right Triangle, Isosceles, Congruence, Angle

Geometry Problem
Click the figure below to see the complete problem 597.

Geometry Problem 597: Quadrilateral, Right Triangle, Isosceles, Congruence, Angle.

Posted by Antonio Gutierrez at 10:33 AM
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4 comments:

  1. ibrahimelsagerApril 29, 2011 at 3:59 PM

    http://www.mathmontada.net/vb/showpost.php?p=20572&postcount=137

    ReplyDelete
  2. AnonymousMay 1, 2011 at 2:27 PM

    x=120 Degrees.

    ReplyDelete
  3. PravinMay 2, 2011 at 5:12 AM

    Complete the rectangle ABDF.
    Join BF to intersect AD at O.
    AC = BD = AF
    CB = CD and OB = OD imply CO is the
    perpendicular bisector of BD
    and hence of AF as well.
    Follows AC = FC and triangle ACF is equilateral.
    So x = supplement of angle CAF = 120 degrees.

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  4. Sumith PeirisJuly 2, 2015 at 3:05 AM

    Drop perpendiculars CG and CF to AB and BD. Then BGCF is a rectangle and FC= BG=1/2BD=AC. So Tr. FAC is 30-60-90.
    Hence x = 120

    Sumith Peiris
    Moratuwa
    Sri Lanka

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