Thursday, March 3, 2011

Problem 588: Triangle, Incenter, Incircle, Tangency Point, Midpoint, Distance, Sum

Geometry Problem
Click the figure below to see the complete problem 588.

Problem 588: Triangle, Incenter, Incircle, Tangency Point, Midpoint, Distance, Sum.
Zoom at: Geometry Problem 588

Posted by Antonio Gutierrez at 7:28 PM
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3 comments:

  1. c .t . e. oMarch 4, 2011 at 12:30 AM

    from 587
    x = (a-c)/2, d = (a-b)/2, e = (b-c)/2
    d + e = (a-b)/2 + (b-c)/2 = (a-c)/2 = x

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  2. AnonymousMarch 4, 2011 at 1:57 AM

    Using problem 587 and a similar method of proof, it is very easy.

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  3. MarcoDecember 26, 2023 at 10:17 PM

    From problem 587, x=(a-c)/2=CH-AG=(CF-HF)-(AE+EG)=(CD-e)-(AD+d)=2x-d-e
    So, x=d+e

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