Monday, January 17, 2011

Problem 568: Triangle, Excircles, Tangency Point, Congruence

Geometry Problem
Click the figure below to see the complete problem 568.

Problem 568: Triangle, Excircles, Tangency Point, Congruence.
Zoom at: Geometry Problem 568

Posted by Antonio Gutierrez at 6:21 PM
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2 comments:

  1. Peter TranJanuary 17, 2011 at 7:19 PM

    http://img10.imageshack.us/img10/6161/problem568.png

    BE and BD are external angle bisector of angle (ABC) ( see attached picture)
    So D,B,E are collinear and angle(DBF)= angle (GBE) ( half of vertical angles)
    So angle(FDB)=angle(BEG) ( complement angles to congruence angles)
    Triangles DHE is isosceles and DH=EH

    Peter Tran

    ReplyDelete
  2. c.t.e.o.January 14, 2021 at 1:59 PM

    https://photos.app.goo.gl/ZbmRaEjfCNtP2yLX8

    ReplyDelete

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