Sunday, September 26, 2010

Problem 522: Right Triangle, Circle, Diameter, Tangent

Geometry Problem
Level: High School, SAT Prep, College geometry.
Click the figure below to see the complete problem 522 about Right Triangle, Circle, Diameter, Tangent.

Problem 522: Right Triangle, Circle, Diameter, Tangent

Posted by Antonio Gutierrez at 7:28 PM
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4 comments:

  1. c .t . e. oSeptember 27, 2010 at 8:26 AM

    ▲ADE ~ ▲ABE => ED/AE = BE/x
    ▲EDC ~ ▲AEC => ED/AE = DC/5
    => x = 5

    ReplyDelete
  2. AnonymousSeptember 28, 2010 at 6:52 AM

    http://ahmetelmas-geo-geo-antonio.blogspot.com/2010/09/prb522.html

    ReplyDelete
  3. Sumith PeirisFebruary 12, 2016 at 8:03 AM

    Because FD // BC, FE = DE = m say

    If also BE = DC = p and AE = n

    p/m = x/n = 5/n since Tr.s BEF and ABE are similar and DEC and ACE are similar

    So x = 5

    Sumith Peiris
    Moratuwa
    Sri Lanka

    ReplyDelete
  4. Sumith PeirisMay 8, 2019 at 3:17 AM

    Solution 2

    FD//BC, ODEC is a kite as before.

    So AE bisects < BAC

    So x/BE = AC/5 or x = AC.BE/5 = CD.AC/5 = 25/5 = 5

    Sumith Peiris
    Moratuwa
    Sri Lanka

    ReplyDelete

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