Geometry Problem
Click the figure below to see the complete problem 515 about Triangle, Double Angle, Altitude, Measure.
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Complete Problem 515
Level: High School, SAT Prep, College geometry
Sunday, August 29, 2010
Problem 515: Triangle, Double Angle, Altitude, Measure
See also:
Complete Problem 515
Level: High School, SAT Prep, College geometry
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Locate E on CD s.t. DE=d. Now triangles BAD & BED are congruent with BE=c and /_BED=2α which makes /_EBC=2α-α=α or BE=EC=c. Hence, e=DE+EC=d+c
ReplyDeleteAjit
extend CA to G, AG = AB => ▲GBC isoceles =>
ReplyDeleteBD median
Extend AC to the left and locate point E such that AE=c
ReplyDeleteTriangle ABE isosceles with angle(AEB)=alpha
so triangle EBC isosceles and BD is the median of isosceles tri. EBC
we have DC=DE=DA+AE=d+c
Peter Tran
Let point E on line AC, and BE=BC.
ReplyDeleteAngle BEA=angle BCA=alpha.
AB=AE, since angle ABE=alpha (2xalpha - alpha).
Point D=midpoint of EC---> EA+AD=DC (c+d=e)