Geometry Problem

Click the figure below to see the complete problem 515 about Triangle, Double Angle, Altitude, Measure.

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Complete Problem 515

Level: High School, SAT Prep, College geometry

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## Sunday, August 29, 2010

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Problem 515: Triangle, Double Angle, Altitude, Measure

See also:

Complete Problem 515

Level: High School, SAT Prep, College geometry

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Geometry Problem

Click the figure below to see the complete problem 515 about Triangle, Double Angle, Altitude, Measure.

See also:

Complete Problem 515

Level: High School, SAT Prep, College geometry

Labels:
altitude,
double angle,
measurement,
triangle

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Locate E on CD s.t. DE=d. Now triangles BAD & BED are congruent with BE=c and /_BED=2α which makes /_EBC=2α-α=α or BE=EC=c. Hence, e=DE+EC=d+c

ReplyDeleteAjit

extend CA to G, AG = AB => ▲GBC isoceles =>

ReplyDeleteBD median

Extend AC to the left and locate point E such that AE=c

ReplyDeleteTriangle ABE isosceles with angle(AEB)=alpha

so triangle EBC isosceles and BD is the median of isosceles tri. EBC

we have DC=DE=DA+AE=d+c

Peter Tran

Let point E on line AC, and BE=BC.

ReplyDeleteAngle BEA=angle BCA=alpha.

AB=AE, since angle ABE=alpha (2xalpha - alpha).

Point D=midpoint of EC---> EA+AD=DC (c+d=e)