Sunday, August 15, 2010

Problem 503: Triangle with Three Squares, Perpendicular, Congruence, Concurrency

Geometry Problem
Click the figure below to see the complete problem 503 about Triangle with Three Squares, Perpendicular, Congruence, Concurrency.

Problem 503. Triangle with Three Squares, Perpendicular, Congruence, Concurrency


See also:
Complete Problem 503

Level: High School, SAT Prep, College geometry

1 comment:

  1. There is a minor typo error in my previous comment. Below is the corrected copy

    Call Q the projection of M over AB
    We have QM=QB and ang (MQB)=90
    And QO=QN and ang ( OQN)=90 ( See Problem 497)
    Triangle MQN congruence with tri. BQO (case SAS)
    Tri. MQN is the image of Tri. QBO in the rotational transformation of center Q and angle of rotational=90
    So MN=BO and MN perpen. To BO.
    With same reason as above we also have MP perpen. To NO and AM perpen. To MO.
    P is the orthocenter of triangle MNO . AN, BO and CM concurrence at P

    Peter Tran

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