Geometry Problem

Click the figure below to see the complete problem 503 about Triangle with Three Squares, Perpendicular, Congruence, Concurrency.

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Complete Problem 503

Level: High School, SAT Prep, College geometry

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## Sunday, August 15, 2010

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Problem 503: Triangle with Three Squares, Perpendicular, Congruence, Concurrency

See also:

Complete Problem 503

Level: High School, SAT Prep, College geometry

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Geometry Problem

Click the figure below to see the complete problem 503 about Triangle with Three Squares, Perpendicular, Congruence, Concurrency.

See also:

Complete Problem 503

Level: High School, SAT Prep, College geometry

Labels:
concurrent,
congruence,
perpendicular,
square,
triangle

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There is a minor typo error in my previous comment. Below is the corrected copy

ReplyDeleteCall Q the projection of M over AB

We have QM=QB and ang (MQB)=90

And QO=QN and ang ( OQN)=90 ( See Problem 497)

Triangle MQN congruence with tri. BQO (case SAS)

Tri. MQN is the image of Tri. QBO in the rotational transformation of center Q and angle of rotational=90

So MN=BO and MN perpen. To BO.

With same reason as above we also have MP perpen. To NO and AM perpen. To MO.

P is the orthocenter of triangle MNO . AN, BO and CM concurrence at P

Peter Tran