Geometry Problem
Click the figure below to see the complete problem 485 about Square, Side, Circles, Tangent, Radius, Measurement.
See also:
Complete Problem 485
Level: High School, SAT Prep, College geometry
Wednesday, July 28, 2010
Problem 485: Square, Side, Circles, Tangent, Radius, Measurement
Subscribe to:
Post Comments (Atom)
Draw perpendiculars from centres of C2 & C3 (labelled as F & G) to AB & AD intersecting in E. EFG is a rt. angled triangle giving us FG^2= EF^2 + EG^2 or (a/2-x)^2+(a/4)^2=(a/4+x)^2 which can be solved to obtain x=a/6.
ReplyDeleteAjit
let be E center of C1,F center of C3
ReplyDeleteu=mes(<CBE),v=mes(<ABF)
in the corner B
2u+2v=90;u+v=45
tan(u)=1/2,tan(v)=2x/a=tan(45-u)=1/3
x=a/6
.-.
We can form a right triangle of by drawing parallels to AB thro O1 and O3
ReplyDeleteThis right triangle will have sides = to a/2-x, a/2+x and a/4
Now use Pyhagoras and the result follows
Sumith Peiris
Moratuwa
Sri Lanka
No Pythagoras T
ReplyDeletehttps://photos.app.goo.gl/MSNnCtt8RVeG7DK96