Proposed Problem
Click the figure below to see the complete problem 422 about Triangle, 24, 30 degree, Angle, Congruence.
See also:
Complete Problem 422
Level: High School, SAT Prep, College geometry
Wednesday, January 27, 2010
Problem 422: Triangle, 24, 30 degree, Angle, Congruence
Subscribe to:
Post Comments (Atom)
This comment has been removed by a blog administrator.
ReplyDeleteIs the answer 48 degrees????
ReplyDeleteThe answer is not 48 degrees
ReplyDeletewith the formula siny=sin(180-y) and the sine rule in ABD and BDC
ReplyDeletesin24.sin(150-x)=sin30.sinx
sin(150-x)=sin(30+x)=sin30.cosx+cos30.sinx
after substitution and division by cosx
we have
tanx=sin30.sin24/(sin30-sin24.cos30)=tan54
x=54
.-.
Here goes again:
ReplyDeletehttp://img218.imageshack.us/img218/4855/solg.png
Antonio: i can't directly copy a link when posting here, why? also, do you have any mail so that i can make you some questions?
Ale:
ReplyDeleteTry to use html tags on your comments:
The HTML for a basic link looks like this:
< a href="http://URL">TEXT< /a>
This text will be highlighted, and when clicked on, the browser window will go to the address specificed by the URL.
My email address is on the web pages.
Problem 422
ReplyDeleteForming an equilateral triangle ABΕ (D is an interior point of triangle ABE). Then < AEB = 60 = 2.30 = 2.ACB so E is circumcenter of triangle ABC.Therefore AB=BE=AE=EC=DC and
<EAC=36=<ECA, <EDC=72 so <DEA=<DAE=36 then AD=DE. Is triangle ABD=triangle EBD
So <DBA=<DBE=30. Therefore <BDC=x=30+24=54.
APOSTOLIS MANOLOUDIS 4 HIGH SHCOOL OF KORYDALLOS PIRAEUS GREECE