Wednesday, January 27, 2010

Problem 422: Triangle, 24, 30 degree, Angle, Congruence

Proposed Problem
Click the figure below to see the complete problem 422 about Triangle, 24, 30 degree, Angle, Congruence.

 Problem 422: Triangle, 24, 30 degree, Angle, Congruence.
See also:
Complete Problem 422

Level: High School, SAT Prep, College geometry

7 comments:

  1. This comment has been removed by a blog administrator.

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  2. Is the answer 48 degrees????

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  3. with the formula siny=sin(180-y) and the sine rule in ABD and BDC
    sin24.sin(150-x)=sin30.sinx
    sin(150-x)=sin(30+x)=sin30.cosx+cos30.sinx
    after substitution and division by cosx
    we have
    tanx=sin30.sin24/(sin30-sin24.cos30)=tan54
    x=54
    .-.

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  4. Here goes again:

    http://img218.imageshack.us/img218/4855/solg.png

    Antonio: i can't directly copy a link when posting here, why? also, do you have any mail so that i can make you some questions?

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  5. Ale:
    Try to use html tags on your comments:
    The HTML for a basic link looks like this:
    < a href="http://URL">TEXT< /a>

    This text will be highlighted, and when clicked on, the browser window will go to the address specificed by the URL.

    My email address is on the web pages.

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  6. Problem 422
    Forming an equilateral triangle ABΕ (D is an interior point of triangle ABE). Then < AEB = 60 = 2.30 = 2.ACB so E is circumcenter of triangle ABC.Therefore AB=BE=AE=EC=DC and
    <EAC=36=<ECA, <EDC=72 so <DEA=<DAE=36 then AD=DE. Is triangle ABD=triangle EBD
    So <DBA=<DBE=30. Therefore <BDC=x=30+24=54.
    APOSTOLIS MANOLOUDIS 4 HIGH SHCOOL OF KORYDALLOS PIRAEUS GREECE

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