Proposed Problem
Click the figure below to see the complete problem 374 about Triangle, Incenter, Internal Angle Bisectors.
See more:
Complete Geometry Problem 374
Level: High School, SAT Prep
Tuesday, October 27, 2009
Problem 374: Triangle, Incenter, Internal Angle Bisectors
Subscribe to:
Post Comments (Atom)
A+B+C=180, since I is the incenter of the triangle ABC, alpha=90-B/2+90-C/2=A/2+90
ReplyDelete