Proposed Problem

Click the figure below to see the complete problem 299 about Intersecting Circles, Chord, Secant, Midpoint, Congruence.

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Complete Problem 299

Collection of Geometry Problems

Level: High School, SAT Prep, College geometry

## Monday, June 8, 2009

### Problem 299: Intersecting Circles, Chord, Secant, Midpoint, Congruence

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Triangles ACE and BCG are congruent.

ReplyDeleteAE and BG are parallel.

ADGB is an isosceles trapezoid.

DG is equal to AB and so is DH.

From 298 we get that GCH and ECF are similar hence GH//EF.

ReplyDeleteFrom 297 we get that DO is perpendicular to EF so it is also perpendicular to GH.

Therefore DO is the perpendicular bisector of GH hence DG = DH.