Monday, June 8, 2009

Problem 299: Intersecting Circles, Chord, Secant, Midpoint, Congruence

Proposed Problem
Click the figure below to see the complete problem 299 about Intersecting Circles, Chord, Secant, Midpoint, Congruence.

 Problem 299: Intersecting Circles, Chord, Secant, Midpoint, Congruence.
See also:
Complete Problem 299
Collection of Geometry Problems

Level: High School, SAT Prep, College geometry

2 comments:

  1. Triangles ACE and BCG are congruent.
    AE and BG are parallel.
    ADGB is an isosceles trapezoid.
    DG is equal to AB and so is DH.

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  2. From 298 we get that GCH and ECF are similar hence GH//EF.
    From 297 we get that DO is perpendicular to EF so it is also perpendicular to GH.
    Therefore DO is the perpendicular bisector of GH hence DG = DH.

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