Wednesday, June 3, 2009

Problem 296: Intersecting Circles, Chord, Radius, Angle, Perpendicular

Proposed Problem
Click the figure below to see the complete problem 296 about Intersecting Circles, Chord, Radius, Angle, Perpendicular.

 Problem 296: Intersecting Circles, Chord, Radius, Angle, Perpendicular.
See also:
Complete Problem 296
Collection of Geometry Problems

Level: High School, SAT Prep, College geometry

4 comments:

  1. Join OB and produce OC to DE at a point F.
    Let angle OBC=y,
    Then angle COB=180-2y
    angle BAC=90-y=angle BED
    Also, angle ECF=y
    So, angle EFC=90, OC is perpendicular to DE

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  2. Let < EDA = @ then @ = < ABE = < AOC /2 hence < ACO = 90 - @ hence OC is perpendicular to DE

    Sumith Peiris
    Moratuwa
    Sri Lanka

    ReplyDelete
  3. See diagram here.
    Let AB and DE intersect in F and OQ and circle O intersect in G
    Since AB ⊥ OQ , OC ⊥ DE ⇔ ∠COQ = ∠BFD
    But ∠BFD = ∠BAD - ∠ADF = ∠BAC - ∠ABC
    Since A and B are symmetric versus OG, ∠BAC - ∠ABC = 2. ∠CAG = ∠COQ QED

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  4. The correct link to the diagram is here.

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