Proposed Problem
See complete Problem 273 at:
gogeometry.com/problem/p273_triangle_perpendicular_squares_areas.htm
Level: High School, SAT Prep, College geometry
Sunday, March 22, 2009
Problem 273: Triangle, Perpendiculars, Area of Squares
Labels:
area,
perpendicular,
square,
triangle
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S1 = AD^2 = OA^2 - OD^2
ReplyDeleteS3 = BE^2 = OB^2 - OE^2
S5 = CF^2 = OC^2 - OF^2
Or,S1+ S3 + S5= OA^2-OD^2+OB^2 -OE^2+OC^2-OF^2
=(OB^2-OD^2)+(OC^2-OE^2)+(OA^2-OF^2)
= BD^2 + CE^2 + AF^2
= S2 + S4 + S6
QED
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