Friday, January 2, 2009

Elearn Geometry Problem 214: Quadrilateral, Angle Bisectors

Geometry Problem 214: Quadrilateral, Angle Bisectors.

See complete Problem 214 at:
gogeometry.com/problem/p214_quadrilateral_angle_bisector.htm

Level: High School, SAT Prep, College geometry

Posted by Antonio Gutierrez at 3:50 AM
Labels: , , ,

2 comments:

  1. AnonymousJanuary 2, 2009 at 1:48 PM

    BAC + CDA + ABC + DCB = 360 (1)
    B/2 + C/2 + x = 180 (2)

    B + C = 360 - 2x
    B + C = 360 - A - D

    then 360 - 2x = 360 - A - D
    -2x = -A -D
    x = (A-D)/2

    ReplyDelete
  2. AnonymousNovember 6, 2009 at 1:15 PM

    1st mistake to the anonunous solution :
    In the 1st equation "BAC" should be replaced with BAD.
    2nd mistake : if -2X=-A-D then 2X=A+D, so X=(A+D)/2 and not X=(A-D)/2.
    Hoever his solution (with the above corrections) is right and elegant.
    G. Platis

    ReplyDelete

Share your solution or comment below! Your input is valuable and may be shared with the community.

Subscribe to: Post Comments (Atom)