See complete Problem 162 at:
www.gogeometry.com/problem/p162_parallelogram_triangle_area.htm
Parallelogram, Triangles, Areas. Level: High School, SAT Prep, College geometry
Post your solutions or ideas in the comments.
Sunday, August 24, 2008
Elearn Geometry Problem 162
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From E draw a line parallel to AB (& DC) meeting FG in H. Now triangles FBM a& EMH are similar. Hence Tr FBM/Tr.EMH =BF^2/EH^2 = a^2/(ka)^2 or
ReplyDeleteS1 = Tr. EMH/k^2 Similarly S2 = Tr.ENH/k^2 Hence, S1+S2 = Tr. EMH/k^2 + Tr.ENH/k^2
= Tr. EMH/k^2
or S1 + S2 = Tr. EMH/k^2 = S/k^2. Hence etc.
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