Monday, May 19, 2008

Geometry Problem 93

See complete Problem 93
Similar Triangles, Circumcircles, Parallelogram. Level: High School, SAT Prep, College geometry

Post your solutions or ideas in the comments.

1 comment:

  1. 1. If angle DAC is x, then Angle GMC=Angle EFG=Angle BDF=x
    2. Then angle EO2G=2x; Angle O1OC=2x (According to the rule that the central angle is two times that of peripheral angle on a circle)
    3. According to the same rule angle GO3C=2x= angle BO1O2; then Angle OO1O2= Angle GO3O=180-2x
    4. Because alternate angles are same; the O1OO3O2 is a parralelogram