Online Geometry theorems, problems, solutions, and related topics.
Geometry Problem. Post your solution in the comments box below.Level: Mathematics Education, High School, Honors Geometry, College.Click the figure below to view the complete problem 1039.
Join AD. Since ∠FCB = ∠EDB = ∠EAD, so A,C,D,F are concyclic. Since ∠FAC = ∠DCA = ∠BFD, thus FD//AC.
< FCD = < BDE = < DAE hence ACDF is cyclic so < EDF = < CFD = < CAD = < ACF since < BAC = < ACB and < DAF = DCFHence FD // ACSumith PeirisMoratuwaSri Lanka