Geometry Problem. Post your solution in the comments box below.

Level: Mathematics Education, High School, Honors Geometry, College.

Click the figure below to view the complete problem 1039.

## Saturday, August 23, 2014

### Geometry Problem 1039: Isosceles Triangle, Circle, Tangent Line, Parallel Line

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Join AD.

ReplyDeleteSince ∠FCB = ∠EDB = ∠EAD,

so A,C,D,F are concyclic.

Since ∠FAC = ∠DCA = ∠BFD,

thus FD//AC.

< FCD = < BDE = < DAE hence ACDF is cyclic so < EDF = < CFD = < CAD = < ACF since < BAC = < ACB and < DAF = DCF

ReplyDeleteHence FD // AC

Sumith Peiris

Moratuwa

Sri Lanka