Geometry Problem

Click the figure below to see the complete problem 588.

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## Thursday, March 3, 2011

### Problem 588: Triangle, Incenter, Incircle, Tangency Point, Midpoint, Distance, Sum

Labels:
incenter,
incircle,
midpoint,
sum of segments,
tangency point,
triangle

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from 587

ReplyDeletex = (a-c)/2, d = (a-b)/2, e = (b-c)/2

d + e = (a-b)/2 + (b-c)/2 = (a-c)/2 = x

Using problem 587 and a similar method of proof, it is very easy.

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