Geometry Problem

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## Monday, January 17, 2011

### Problem 568: Triangle, Excircles, Tangency Point, Congruence

Labels:
congruence,
excircle,
tangency point,
triangle

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http://img10.imageshack.us/img10/6161/problem568.png

ReplyDeleteBE and BD are external angle bisector of angle (ABC) ( see attached picture)

So D,B,E are collinear and angle(DBF)= angle (GBE) ( half of vertical angles)

So angle(FDB)=angle(BEG) ( complement angles to congruence angles)

Triangles DHE is isosceles and DH=EH

Peter Tran