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Wednesday, November 27, 2019
Dynamic Geometry 1449: Salmon Line
Interactive step-by-step animation using GeoGebra. Post your solution in the comment box below. Level: Mathematics Education, High School, Honors Geometry, College.
https://photos.app.goo.gl/33524ymivbNG4dpB6 Define points E’, F’, G’ per sketch Note that E’, F’, G’ are midpoints of AE, AF, AG C, G,D are the image of O2,G, O3 in the Homothety transformation So C, G, D are collinear. Similarly C,B,E and B, F, D are colinear. Quadrilateral ABCD is cyclic => ∠ (ABE)= ∠ (ADG) => ∠ (EAB)= ∠ (DAG) ( complementary angles) So ∠ (BFE)= ∠ (GFD) => E,F,G are colinear
https://photos.app.goo.gl/33524ymivbNG4dpB6
ReplyDeleteDefine points E’, F’, G’ per sketch
Note that E’, F’, G’ are midpoints of AE, AF, AG
C, G,D are the image of O2,G, O3 in the Homothety transformation
So C, G, D are collinear.
Similarly C,B,E and B, F, D are colinear.
Quadrilateral ABCD is cyclic => ∠ (ABE)= ∠ (ADG) => ∠ (EAB)= ∠ (DAG) ( complementary angles)
So ∠ (BFE)= ∠ (GFD) => E,F,G are colinear