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From Pythagoras,CD^2 = CE^2 - DE^2 = BD^2 - BC^2 and so BD^2 + DE^2 = BC^2 + CE^2Hence S1 + S4 = S2 + S3Sumith PeirisMoratuwaSri Lanka
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From Pythagoras,
ReplyDeleteCD^2 = CE^2 - DE^2 = BD^2 - BC^2 and so
BD^2 + DE^2 = BC^2 + CE^2
Hence S1 + S4 = S2 + S3
Sumith Peiris
Moratuwa
Sri Lanka