Saturday, May 18, 2019

Geometry Problem 1434: Equilateral Triangle, Tangent Circles, Tangent Lines, Arithmetic Mean, Measurement

Geometry Problem. Post your solution in the comment box below.
Level: Mathematics Education, High School, Honors Geometry, College.

Details: Click on the figure below.

Geometry Problem 1434: Equilateral Triangle, Tangent Circles, Tangent Lines, Arithmetic Mean, Measurement, Tutoring.
at

2 comments:

  1. Peter TranMay 19, 2019 at 9:49 AM

    https://photos.app.goo.gl/hawHpVWSb5MK1TVcA

    Let BO meet AC at P and circle O at Q
    Since ABC is equilateral , ^(AOC)=120 => P is the midpoint of OQ
    Per the result of problem 1433 we have
    BN=2.PF and BM=2.PD
    So BM+BN=2(PF+PD)=2.DF

    ReplyDelete
  2. AnonymousMay 19, 2019 at 9:54 PM

    Trough BO, make diameter BH, H on circomference,intersect with AC at K,
    From 1433, BN= 2 KF,
    BM=2DK,
    so BM+BN= 2(DF)

    ReplyDelete

Share your solution or comment below! Your input is valuable and may be shared with the community.