x = Angle ADB (ADB is the angle subtended by arc AB at the circumference of the circle through A,D,B) = Half of angle AO'B (AO'B is the angle subtended by arc AB at centre O' of circle through A,D,B) = Half of (180 deg - angle ACB) (AO'BC is a cyclic quadrilateral) = Half of (180 - 50) deg = 65 deg
x = Angle ADB
ReplyDelete(ADB is the angle subtended by arc AB at the circumference of the circle through A,D,B)
= Half of angle AO'B
(AO'B is the angle subtended by arc AB at centre O' of circle through A,D,B)
= Half of (180 deg - angle ACB)
(AO'BC is a cyclic quadrilateral)
= Half of (180 - 50) deg
= 65 deg
x=65 Degrees
ReplyDelete