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[DBE]=0.5(p-b).r_A[FCE]=0.5(p-c).r_Ap-b+p-c=a[BEC]=0.5a.r_A=[DBE]+[FCE]we haveS1+[BGE]+S2+[CHE]=S3+[BGE]+[CHE]S1+S2=S3.-.
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[DBE]=0.5(p-b).r_A
ReplyDelete[FCE]=0.5(p-c).r_A
p-b+p-c=a
[BEC]=0.5a.r_A=[DBE]+[FCE]
we have
S1+[BGE]+S2+[CHE]=S3+[BGE]+[CHE]
S1+S2=S3
.-.
Good work
ReplyDeletehttps://photos.app.goo.gl/5f4LruRNNUCYWmEu8
ReplyDelete