This space is for community interaction. Solutions posted here are provided by our visitors.
Triangles ABC,BDE,GFE&GMc are similar; hence ther circumradii will be proportional to their corresponding sides. Thus,R1/R=BE/BC,R2/R=GE/BC & R3/R=GC/BC. Or R1/R+R2/R+R3/R=(BG+EG+GC)/BC=BC/BC=1 or R1 + R2 + R3 = RAjit: ajitathle@gmail.com
Share your solution or comment below! Your input is valuable and may be shared with the community.
Triangles ABC,BDE,GFE&GMc are similar; hence ther circumradii will be proportional to their corresponding sides. Thus,R1/R=BE/BC,R2/R=GE/BC & R3/R=GC/BC. Or R1/R+R2/R+R3/R=(BG+EG+GC)/BC=BC/BC=1 or R1 + R2 + R3 = R
ReplyDeleteAjit: ajitathle@gmail.com