Online Geometry theorems, problems, solutions, and related topics.
Geometry Problem. Post your solution in the comments box below.Level: Mathematics Education, High School, Honors Geometry, College.Click the figure below to view the complete problem 993
<CBD=(<CBA=<ECD)+(<DBA=<EDC)=180-<CED, which makes CEDB cyclic and all points CEDBF lie on a circle. Then it is obvious that <FBE=<FDE=90.It also follows that <QFB=<DCB=<AOB/2=<QOB which makes points OQBF lie on a circle.