Sunday, March 2, 2014

Dynamic Geometry: Brahmagupta Theorem, Cyclic Quadrilateral, Perpendicular Diagonals, Midpoint

Dynamic Geometry. GeoGebra, HTML5 Animation for iPad and Nexus.

Level: Mathematics Education, School, Honors Geometry, College.

Click the figure below to view the dynamic geometry demonstration.

Dynamic Geometry: Brahmagupta Theorem, Cyclic Quadrilateral, Perpendicular Diagonals, Midpoint

1 comment:

  1. /_C = /_D = /_ HEA = /_CEM
    So MC = ME
    /_MBE = /_MEB (/_s complimentary to /_C & /_CEM are also equal)
    So ME = MB
    Hence MB = MC

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