Online Geometry theorems, problems, solutions, and related topics.
Geometry ProblemClick the figure below to see the complete problem 604.
http://img37.imageshack.us/img37/1471/problem604.pngLet K is the projection of B over AE and L is the projection of E over AB ( see picture)We have area(GAEF)=Area(ABH)+10=AE .BK= AB. EL= 2.* Area(ABE)=Area(ABCD)but Area(ABCD)=x+ Area(ABH)So x=10Peter Tran
Extend GF and DE to meet at K∆AGB≡∆EFKUsing notation (…) for area(EFK) = (AGB) = 3(BHEK) = 7 + 3 = 10Denote (HCE) by y(BCK) = 10 + yNext ∆ADE ≡ ∆BCK(ADE )= (BCK)x+ y = 10 + yx = 10