Thursday, May 13, 2010

Problem 451: Triangle, Median, Congruence, Proportional Segments

Geometry Problem
Click the figure below to see the complete problem 451 about Triangle, Median, Congruence, Proportional Segments.

Problem 451: Triangle, Median, Congruence, Proportional Segments.
See also:
Complete Problem 451
Level: High School, SAT Prep, College geometry

3 comments:

  1. draw CKL//EF, K on BD, L on AB
    ▲BFG ~ ▲BLK, ▲BGE ~ ▲BKC
    => KL = kx, KC = ky, (k koeficent = BF/FL)
    from P 450
    kx/ky = a/c

    x/y = a/c
    -----------------------------------------

    ReplyDelete
  2. A nice solution

    ReplyDelete
  3. It's not difficult to see that

    S(ABG) = S(CBG)

    So c.x sin < BFE = a.y sin < BEF

    Hence cx = ay

    Sumith Peiris
    Moratuwa
    Sri Lanka

    ReplyDelete