Geometry Problem

Click the figure below to see the complete problem 451 about Triangle, Median, Congruence, Proportional Segments.

See also:

Complete Problem 451

Level: High School, SAT Prep, College geometry

## Thursday, May 13, 2010

### Problem 451: Triangle, Median, Congruence, Proportional Segments

Labels:
congruence,
median,
proportions,
triangle

Subscribe to:
Post Comments (Atom)

draw CKL//EF, K on BD, L on AB

ReplyDelete▲BFG ~ ▲BLK, ▲BGE ~ ▲BKC

=> KL = kx, KC = ky, (k koeficent = BF/FL)

from P 450

kx/ky = a/c

x/y = a/c

-----------------------------------------

A nice solution

ReplyDeleteIt's not difficult to see that

ReplyDeleteS(ABG) = S(CBG)

So c.x sin < BFE = a.y sin < BEF

Hence cx = ay

Sumith Peiris

Moratuwa

Sri Lanka