Proposed Problem

Click the figure below to see the complete problem 411 about Triangle, Median, Angles.

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Complete Problem 411

Level: High School, SAT Prep, College geometry

## Thursday, December 31, 2009

### Problem 411: Triangle, Median, Angles

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http://geometri-problemleri.blogspot.com/2009/12/problem-59-ve-cozumu.html

ReplyDeletedraw DE middle line of ABC

ReplyDeleteDE = X = 1/2 AC = 6

simular triangles x=6

ReplyDeletex = 5.443

ReplyDeleteTo Anonymous, March 23, 2010 5:14 AM

ReplyDeletex = 5.443 (Not correct)

Hint : 51+51+78 = 180

ReplyDeleteI'm korean, i am interested in your math problems,,

ReplyDeletei solved it that way : straight AC so DA parallel ED.. and triangle BEA is isosceles triangle,, finally 1:2=x:12 x=6 am i right?

i'm sorry i can't write english well,,

To Anonymous, problem #411: Your answer is right (I think that in your solution: DA is parallel to BE)

ReplyDeleteProblem 411

ReplyDeleteIn extension of the CA to get A point E such that EA=AD=x ,so triangle BAD= triangle BAE(<EAB=<BAD=51) then BE=BD and <EBA=<ABC, so BE/BC=EA/AC or ½=x/12

Therefore x=6.