Thursday, December 31, 2009

Problem 411: Triangle, Median, Angles

Proposed Problem
Click the figure below to see the complete problem 411 about Triangle, Median, Angles.

Problem 411: Triangle, Median, Angles.
See also:
Complete Problem 411
Level: High School, SAT Prep, College geometry

9 comments:

  1. http://geometri-problemleri.blogspot.com/2009/12/problem-59-ve-cozumu.html

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  2. draw DE middle line of ABC

    DE = X = 1/2 AC = 6

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  3. To Anonymous, March 23, 2010 5:14 AM

    x = 5.443 (Not correct)

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  4. I'm korean, i am interested in your math problems,,
    i solved it that way : straight AC so DA parallel ED.. and triangle BEA is isosceles triangle,, finally 1:2=x:12 x=6 am i right?
    i'm sorry i can't write english well,,

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  5. To Anonymous, problem #411: Your answer is right (I think that in your solution: DA is parallel to BE)

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  6. Problem 411
    In extension of the CA to get A point E such that EA=AD=x ,so triangle BAD= triangle BAE(<EAB=<BAD=51) then BE=BD and <EBA=<ABC, so BE/BC=EA/AC or ½=x/12
    Therefore x=6.

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