Wednesday, December 16, 2009

Problem 403. Circular sector, 90 degrees, Circle, Semicircle, Area

Proposed Problem
Click the figure below to see the complete problem 403 about Circular sector, 90 degrees, Circle, Semicircle, Area.

 Problem 403. Circular sector, 90 degrees, Circle, Semicircle, Area.
See also:
Complete Problem 403
Level: High School, SAT Prep, College geometry

1 comments:

  1. Let R radius OC and r radius of circle D.
    Let x distance of D to segment OB. Then x^2 = (R+r)^2-(R-r)^2=4Rr.
    Radius OB is equal to 2R, and then:

    2R=r+sqrt(x^2+r^2) -> R=2r -> S = (pi/4)*R^2 (1)

    A(AOB) = (pi/4)*(2R)^2 - (pi/2)*R^2 = (pi/2)*R^2 = S + S1 + S2 + S3 (2)

    By eq (1) and (2), we've: S = A(AOB)/2 = S1 + S2 + S3

    MIGUE

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