Sunday, January 18, 2009

Elearn Geometry Problem 226: Triangle, Centroid, Perpendiculars

Triangle, Altitude, Angles

See complete Problem 226 at:
gogeometry.com/problem/p226_triangle_centroid_perpendicular.htm

Level: High School, SAT Prep, College geometry

Post your solutions or ideas in the comments.

2 comments:

  1. Hints:
    The median MN of the trapezoid ADFC.
    Triangle NMG similar to triangle BEG.

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  2. If M & N are midpoints of AC & DF resply. then MN=(d+f)/2. And in similar triangles NMG & BEG we've BE/MN = BG/MG = 2. Thus BE = e = 2MN =d + f
    Thanks for the hint, AG!
    Ajit: ajitathle@gmail.com

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