See complete Problem 226 at:

gogeometry.com/problem/p226_triangle_centroid_perpendicular.htm

Level: High School, SAT Prep, College geometry

Post your solutions or ideas in the comments.

## Sunday, January 18, 2009

### Elearn Geometry Problem 226: Triangle, Centroid, Perpendiculars

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Hints:

ReplyDeleteThe median MN of the trapezoid ADFC.

Triangle NMG similar to triangle BEG.

If M & N are midpoints of AC & DF resply. then MN=(d+f)/2. And in similar triangles NMG & BEG we've BE/MN = BG/MG = 2. Thus BE = e = 2MN =d + f

ReplyDeleteThanks for the hint, AG!

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