Sunday, January 4, 2009

Elearn Geometry Problem 218: Right triangle, Altitude and Distances

 Geometry Problem 217: Right triangle, Altitude and Projections.

See complete Problem 218 at:
gogeometry.com/problem/p218_right_triangle_altitude_perpendicular.htm

Level: High School, SAT Prep, College geometry

2 comments:

  1. DFBE is a rectangle so its diagonals meet at the midpoint O of BD. Then
    h=2·OD.
    But EHGF is a trapezium (trapezoid) hence OD=1/2(a+b).
    Finally h=2.OD=a+b

    SG

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  2. Problem 218
    Let FP perpendicular in BD (D,P,B are collinear).Then triangleBFP=triangleHDE(FB=DE,<BFP=<BAC=<EDC ).So BP=EH and FG=PD.
    Therefore BD=BP+PD=EH+FG.
    APOSTOLIS MANOLOUDIS 4 HIGH SHCOOL OF KORYDALLOS PIRAEUS GREECE

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