See complete Problem 194 at:

www.gogeometry.com/problem/p194_area_of_a_triangle_semiperimeter_exradius.htm

Area of a Triangle, Semiperimeter, Exradius. Level: High School, SAT Prep, College geometry

Post your solutions or ideas in the comments.

## Tuesday, October 21, 2008

### Elearn Geometry Problem 194

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ReplyDeleteHints:Area ABC = Area ABE + Area ACE - Area BCE.

Apply Area of a triangle = bh/2 three times.

Let the perpendicular from E_a meet AC extended in M and from E_a to BC in N. We know that AM = s. Therefore Tr. ABC = s*r_a - (CN*r_a+BN*r_a)

ReplyDelete= s*r_a - (CN+BN)*r_a

= s*r_a - BC * r_a

=(s-a)r_a

Ajit: ajitathle@gmail.com

I was wondering if somone could give more detail on either of these proofs. thanksssss

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