Monday, May 19, 2008

Elearn Geometry Problem 75



See complete Problem 75
Three Intersecting Circles, Cyclic Quadrilateral, Angles. Level: High School, SAT Prep, College geometry

Post your solutions or ideas in the comments.

3 comments:

  1. What points are M and N?
    If N is the point where ED meets AH, why is it on circle 5?

    ReplyDelete
  2. Thank you for your comment:
    Line AH and circle 3 meet at M, Line DE and circle 5 meet at N.

    The graphic was updated.

    Thank you.

    ReplyDelete
  3. ang EAH = ang EBM ( AEHD cyclic, arc EFM )
    ang EDH = ang NCH ( NCDH cyclic. arc HGN

    EAH = EAD ( from P 73, AEHD cyclic )
    =>
    EBM = NCH
    =>
    PBQ = PCQ ( as vertikal angles )
    from
    geometry help P39, 16.2

    PBCQ cyclic

    ReplyDelete