Monday, May 19, 2008

Elearn Geometry Problem 72



See complete Problem 72
Intersecting Circles, Cyclic Quadrilateral, Angles, Parallel. Level: High School, SAT Prep, College geometry

Post your solutions or ideas in the comments.

2 comments:

  1. ABCD is cyclic so angle BAD = angle DCF. Similarly DCFE is cyclic and angle DCF = 180 -angle FED. Hence AB is parallel to EF.

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    Replies
    1. What about when BF intersects AE? that is another case, easy to proof, but is part of the problem.

      Greetings

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