See complete Problem 72

Intersecting Circles, Cyclic Quadrilateral, Angles, Parallel. Level: High School, SAT Prep, College geometry

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## Monday, May 19, 2008

### Elearn Geometry Problem 72

Labels:
angle,
circle,
cyclic quadrilateral,
parallel

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ABCD is cyclic so angle BAD = angle DCF. Similarly DCFE is cyclic and angle DCF = 180 -angle FED. Hence AB is parallel to EF.

ReplyDeleteWhat about when BF intersects AE? that is another case, easy to proof, but is part of the problem.

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