tag:blogger.com,1999:blog-6933544261975483399.post9156830088408256524..comments2024-03-26T19:10:02.918-07:00Comments on Go Geometry (Problem Solutions): Geometry Problem 1033: Triangle, Angle Obtuse, Circumcircle, Diameter, AreaAntonio Gutierrezhttp://www.blogger.com/profile/04521650748152459860noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-6933544261975483399.post-30486816417514689182014-07-30T09:39:30.969-07:002014-07-30T09:39:30.969-07:00AC=FD, CE=BF, and AE=BD, so [BFD]=[ECA]=11.
[ABC]...AC=FD, CE=BF, and AE=BD, so [BFD]=[ECA]=11. <br />[ABC]=2+4+11-[ACDF]=2+4+11-2[ACF]=2+4+11-2(2+4)=5Ivan Bazarovnoreply@blogger.comtag:blogger.com,1999:blog-6933544261975483399.post-91597489410229689092014-07-24T16:47:01.365-07:002014-07-24T16:47:01.365-07:00Let S(ABC) be the area of ABC.
S(CDE) = S(ABF) =...Let S(ABC) be the area of ABC. <br /><br />S(CDE) = S(ABF) = 2<br />S(ACDE) = 11+2 = 13<br />S(OCDE) = 13/2<br />S(OCE) = 13/2 - 2 = 9/2<br />S(BCE) = 9<br /><br />S(AEF) = S(BCD) = 4<br />S(ACEF) = 11+4 = 15<br />S(AOEF) = 15/2<br />S(AOE) = 15/2 - 4 = 7/2<br />S(ABE) = 7<br /><br />S(ABC) = 9+7-11 = 5Jacob HA (EMK2000)https://www.blogger.com/profile/17238561555526381028noreply@blogger.com