tag:blogger.com,1999:blog-6933544261975483399.post8461741179848617693..comments2024-03-26T19:10:02.918-07:00Comments on Go Geometry (Problem Solutions): Problem 540: Right Triangle, Square, Parallel, Perpendicular, Dissection, Area, PythagorasAntonio Gutierrezhttp://www.blogger.com/profile/04521650748152459860noreply@blogger.comBlogger1125tag:blogger.com,1999:blog-6933544261975483399.post-79744872531988462102010-11-29T20:31:22.619-08:002010-11-29T20:31:22.619-08:00Denote length AC = b, length BC = a (assume a>b...Denote length AC = b, length BC = a (assume a>b)<br />Extend NB to meet HD at X;<br />Extend AG to meet BX at Y.<br />Easy to derive GH = HX = a - b,<br /> XD = BF = b,<br /> DF = XB = a,<br />A3 = Area of rectangle ACBY <br /> + Area of rectangle BFDX<br /> + Area of square GHXY<br /> = ab + ab + (a-b)^2<br /> = a^2 + b^2<br /> = A1 + A2Pravinhttps://www.blogger.com/profile/05947303919973968861noreply@blogger.com