tag:blogger.com,1999:blog-6933544261975483399.post6865995073561379658..comments2024-03-26T19:10:02.918-07:00Comments on Go Geometry (Problem Solutions): Dynamic Geometry Problem 1445: Van Aubel's theorem, Quadrilateral and Four Squares, CentersAntonio Gutierrezhttp://www.blogger.com/profile/04521650748152459860noreply@blogger.comBlogger1125tag:blogger.com,1999:blog-6933544261975483399.post-34895708753444101732019-11-10T18:15:08.212-08:002019-11-10T18:15:08.212-08:00https://photos.app.goo.gl/ev2e1gUgH5YBtTrP7
Let S...https://photos.app.goo.gl/ev2e1gUgH5YBtTrP7<br /><br />Let S is the midpoint of BD<br />Consider triangle ABD and squares ADKL and ABFE<br />Per the result of problem 497 we have SM=SN and SM⊥SN<br />Consider triangle BCD and squares DCIJ and BCHG <br />We also have SP=SO and SP⊥SO<br />Triangle SOM is congruent to SPN ( case SAS)<br />And triangle SOM is the image of SPN in the rotational transformation, center S<br />And angle of rotation= 90<br />So MO=PN and MO⊥PN<br />Peter Tranhttps://www.blogger.com/profile/02320555389429344028noreply@blogger.com