tag:blogger.com,1999:blog-6933544261975483399.post5514501786567703610..comments2024-03-26T19:10:02.918-07:00Comments on Go Geometry (Problem Solutions): Geometry Problem 94Antonio Gutierrezhttp://www.blogger.com/profile/04521650748152459860noreply@blogger.comBlogger1125tag:blogger.com,1999:blog-6933544261975483399.post-11731811028130373982009-04-25T01:04:00.000-07:002009-04-25T01:04:00.000-07:00Triangles ABC,BDE,GFE&GMc are similar; hence t...Triangles ABC,BDE,GFE&GMc are similar; hence ther circumradii will be proportional to their corresponding sides. Thus,R1/R=BE/BC,R2/R=GE/BC & R3/R=GC/BC. Or R1/R+R2/R+R3/R=(BG+EG+GC)/BC=BC/BC=1 or R1 + R2 + R3 = R<br />Ajit: ajitathle@gmail.comAjithttps://www.blogger.com/profile/00611759721780927573noreply@blogger.com