tag:blogger.com,1999:blog-6933544261975483399.post4400308352705650642..comments2024-03-26T19:10:02.918-07:00Comments on Go Geometry (Problem Solutions): Problem 517: Right Triangle, Six Squares, AreasAntonio Gutierrezhttp://www.blogger.com/profile/04521650748152459860noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-6933544261975483399.post-45488319358890740052010-09-04T16:08:56.373-07:002010-09-04T16:08:56.373-07:00In general, 3x(A4+A1+A2)=A3+A5+A6.
When triangle A...In general, 3x(A4+A1+A2)=A3+A5+A6.<br />When triangle ABC is a right triangle, A3=A4.<br />So, 3x(A1+A2+A3)=A4+A5+A6.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-6933544261975483399.post-18093513480879245202010-09-01T01:42:24.142-07:002010-09-01T01:42:24.142-07:00name AB = a, BC = b, AC = c
S1 + S2 + S3 = a² + b²...name AB = a, BC = b, AC = c<br />S1 + S2 + S3 = a² + b² + (a² + b²) = 2a² + 2b²<br />extend BA,it meet side of A5 in midpoint <br />Str on the right of A5 is (a∙b)/2 =><br />Str/2 = (a∙b)/4 =><br />side of A5 = 4a² + b²<br />Str on the left of A6 is a² + 4b²<br />S5 + S4 + S6 = (4a + b²) + (a² + b²) + (a² + 4b²)<br /> = 6a² + 6b²c .t . e. onoreply@blogger.com