Tuesday, July 30, 2019

Geometry Problem 1442 Triangle, Altitudes, Orthocenter, Perpendicular, Congruent Angles, Similarity, Measurement, iPad apps

Geometry Problem. Post your solution in the comment box below.
Level: Mathematics Education, High School, Honors Geometry, College.

Details: Click on the figure below.

Geometry Problem 1442 Triangle, Altitudes, Orthocenter, Perpendicular, Congruent Angles, Similarity, Measurement, iPad apps, Tutoring.
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3 comments:

  1. Sumith PeirisJuly 31, 2019 at 11:02 AM

    Since < BDE = A, < MBG = (90-A) - (90-C) = C-A = < MCB

    It follows that BM^2 = MG.MC = 10
    So BM = sqrt10

    Sumith Peiris
    Moratuwa
    Sri Lanka

    ReplyDelete
  2. AjitOctober 6, 2019 at 11:14 PM

    Nice solution, Sumith.

    ReplyDelete

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