Thursday, October 20, 2016

Geometry Problem 1275 Equilateral Triangle, Perpendicular, Projection, Metric Relations, Measurement

Geometry Problem. Post your solution in the comment box below.
Level: Mathematics Education, High School, Honors Geometry, College.

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Geometry Problem 1275 Equilateral Triangle, Perpendicular, Projection, Metric Relations, Measurement.
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3 comments:

  1. Sumith PeirisOctober 20, 2016 at 7:47 PM

    If the side of the equilateral triangle be a, then AF = (a+2)/2 and GC = (a-5)/2

    So x = a - (a+2)/2 - (a-5)/2 = 3/2

    Sumith Peiris
    Moratuwa
    Sri Lanka

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  2. APOSTOLIS MANOLOUDISOctober 20, 2016 at 9:52 PM

    Problem 1275
    Suppose that the DF intersects the BC at H, and BK is altitude of triangle ABC (K located on the side AC) ,and HL perpendicular of BK .Then <BDH=60=<BHD so BH=BD=2 and HE=
    BE-BH=5-2=3.Is <LBH=30 so LH=BH/2=2/2=1=KF.So BH/KF=HE/FG or 2/1=3/x or x=3/2.
    APOSTOLIS MANOLOUDIS 4 HIGH SCHOOL KORYDALLOS PIRAEUS GREECE

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  3. Jacob HA (EMK2000)October 20, 2016 at 10:10 PM

    Let BC and DF intersect at H.
    Then BH=BD=2, HE=3.
    Hence, FG=x=3/2.

    ReplyDelete

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