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AB':B'C = (s - a):(s - c)CA':A'B = (s - c):(s - b)BC':C'A = (s - b):(s - a)Product = 1By Ceva, the result follows.
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AB':B'C = (s - a):(s - c)
ReplyDeleteCA':A'B = (s - c):(s - b)
BC':C'A = (s - b):(s - a)
Product = 1
By Ceva, the result follows.