This space is for community interaction. Solutions posted here are provided by our visitors.
angle CBD + angle CED = (angle CBA + angle ABC)+ angle CED= angle ECD + angle EDC + angle CED (*)= 180 degrees=> E, C, B, D are concyclic(*)angle between chord and tangent = angle in the alternate segment
from previous problem, <ABE= <CDE-<ECD, and it is known that <ABD=<CDE, thus <EBD=<ECD and we are done.
Share your solution or comment below! Your input is valuable and may be shared with the community.
angle CBD + angle CED
ReplyDelete= (angle CBA + angle ABC)+ angle CED
= angle ECD + angle EDC + angle CED (*)
= 180 degrees
=> E, C, B, D are concyclic
(*)angle between chord and tangent = angle in the
alternate segment
from previous problem, <ABE= <CDE-<ECD, and it is known that <ABD=<CDE, thus <EBD=<ECD and we are done.
ReplyDelete