If we take the area of semicricle with diameter AO as x and semicircle woth diameter DC as y, then by pythagoras theorem on the trianle ABC, we can say that S+x=S1+S2+y
Now using the pythagoras theorem in right angled triangle DOC, We can say that y=x+S3
putting this value of y in above equation we can prove that
If we take the area of semicricle with diameter AO as x and semicircle woth diameter DC as y, then by pythagoras theorem on the trianle ABC, we can say that
ReplyDeleteS+x=S1+S2+y
Now using the pythagoras theorem in right angled triangle DOC,
We can say that
y=x+S3
putting this value of y in above equation we can prove that
S=S1+S2+S3